Integrand size = 29, antiderivative size = 119 \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=-\frac {64 d^2 \sqrt {c d^2-c e^2 x^2}}{15 c e \sqrt {d+e x}}-\frac {16 d \sqrt {d+e x} \sqrt {c d^2-c e^2 x^2}}{15 c e}-\frac {2 (d+e x)^{3/2} \sqrt {c d^2-c e^2 x^2}}{5 c e} \]
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Time = 0.03 (sec) , antiderivative size = 119, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {671, 663} \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=-\frac {64 d^2 \sqrt {c d^2-c e^2 x^2}}{15 c e \sqrt {d+e x}}-\frac {16 d \sqrt {d+e x} \sqrt {c d^2-c e^2 x^2}}{15 c e}-\frac {2 (d+e x)^{3/2} \sqrt {c d^2-c e^2 x^2}}{5 c e} \]
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Rule 663
Rule 671
Rubi steps \begin{align*} \text {integral}& = -\frac {2 (d+e x)^{3/2} \sqrt {c d^2-c e^2 x^2}}{5 c e}+\frac {1}{5} (8 d) \int \frac {(d+e x)^{3/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx \\ & = -\frac {16 d \sqrt {d+e x} \sqrt {c d^2-c e^2 x^2}}{15 c e}-\frac {2 (d+e x)^{3/2} \sqrt {c d^2-c e^2 x^2}}{5 c e}+\frac {1}{15} \left (32 d^2\right ) \int \frac {\sqrt {d+e x}}{\sqrt {c d^2-c e^2 x^2}} \, dx \\ & = -\frac {64 d^2 \sqrt {c d^2-c e^2 x^2}}{15 c e \sqrt {d+e x}}-\frac {16 d \sqrt {d+e x} \sqrt {c d^2-c e^2 x^2}}{15 c e}-\frac {2 (d+e x)^{3/2} \sqrt {c d^2-c e^2 x^2}}{5 c e} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.47 \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=-\frac {2 \sqrt {c \left (d^2-e^2 x^2\right )} \left (43 d^2+14 d e x+3 e^2 x^2\right )}{15 c e \sqrt {d+e x}} \]
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Time = 2.30 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.43
method | result | size |
default | \(-\frac {2 \sqrt {c \left (-x^{2} e^{2}+d^{2}\right )}\, \left (3 x^{2} e^{2}+14 d e x +43 d^{2}\right )}{15 \sqrt {e x +d}\, c e}\) | \(51\) |
gosper | \(-\frac {2 \left (-e x +d \right ) \left (3 x^{2} e^{2}+14 d e x +43 d^{2}\right ) \sqrt {e x +d}}{15 e \sqrt {-c \,x^{2} e^{2}+c \,d^{2}}}\) | \(55\) |
risch | \(-\frac {2 \sqrt {-\frac {c \left (x^{2} e^{2}-d^{2}\right )}{e x +d}}\, \sqrt {e x +d}\, \left (3 x^{2} e^{2}+14 d e x +43 d^{2}\right ) \left (-e x +d \right )}{15 \sqrt {-c \left (x^{2} e^{2}-d^{2}\right )}\, e \sqrt {-c \left (e x -d \right )}}\) | \(93\) |
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Time = 0.32 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.49 \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=-\frac {2 \, \sqrt {-c e^{2} x^{2} + c d^{2}} {\left (3 \, e^{2} x^{2} + 14 \, d e x + 43 \, d^{2}\right )} \sqrt {e x + d}}{15 \, {\left (c e^{2} x + c d e\right )}} \]
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\[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=\int \frac {\left (d + e x\right )^{\frac {5}{2}}}{\sqrt {- c \left (- d + e x\right ) \left (d + e x\right )}}\, dx \]
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Time = 0.21 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.49 \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=\frac {2 \, {\left (3 \, \sqrt {c} e^{3} x^{3} + 11 \, \sqrt {c} d e^{2} x^{2} + 29 \, \sqrt {c} d^{2} e x - 43 \, \sqrt {c} d^{3}\right )}}{15 \, \sqrt {-e x + d} c e} \]
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Time = 0.28 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.84 \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=\frac {2 \, {\left (\frac {32 \, \sqrt {2} \sqrt {c d} d^{2}}{c} - \frac {60 \, \sqrt {-{\left (e x + d\right )} c + 2 \, c d} d^{2}}{c} + \frac {20 \, {\left (-{\left (e x + d\right )} c + 2 \, c d\right )}^{\frac {3}{2}} c d - 3 \, {\left ({\left (e x + d\right )} c - 2 \, c d\right )}^{2} \sqrt {-{\left (e x + d\right )} c + 2 \, c d}}{c^{3}}\right )}}{15 \, e} \]
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Time = 10.24 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.66 \[ \int \frac {(d+e x)^{5/2}}{\sqrt {c d^2-c e^2 x^2}} \, dx=-\frac {\sqrt {c\,d^2-c\,e^2\,x^2}\,\left (\frac {2\,x^2\,\sqrt {d+e\,x}}{5\,c}+\frac {86\,d^2\,\sqrt {d+e\,x}}{15\,c\,e^2}+\frac {28\,d\,x\,\sqrt {d+e\,x}}{15\,c\,e}\right )}{x+\frac {d}{e}} \]
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